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3 years ago

12

Kona wants to bake 30 loaves of bananas bread and nut bread one is 2.50 and other is 2.75 she wants to make are lasts 44$ write

the inequality

1 answer:

kykrilka [37]3 years ago

6 0

Answer:$79.25

Step-by-step explanation:

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Miriam buys 24 petunia plants and 40 azalea plants

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Answer:

she buys 64 plants in total

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4 years ago

Write an equation of the line passing through the points (4,10) and (-1,-15)

KATRIN_1 [288]

Answer:

Step-by-step explanation:

3 0

4 years ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

3 years ago

PLEASE HELP WITH STEP BY STEP I NEED TO SHOW MY WORK I GO BACK TO CLASS IN 6 MINS

eduard

8 x 615 is 4920.

615
x. 8

______

put a 4 above the one and a 1 above the 6.

6 0

3 years ago

Read 2 more answers

Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)

umka2103 [35]

Answer:

<u>GIVEN :-</u>

∠A = 15°
Length of AB (hypotenuse) = 60 ft

<u>TO FIND :-</u>

Length of BC
Length of AC
Area of ΔABC

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$

<u>SOLUTION :-</u>

In ΔABC ,

$\sin 15 = \frac{BC}{60}$

$=> 0.2588... = \frac{BC}{60}$

$=> BC = (0.2588....) \times 60 = 15.5291.....$ ≈ 15.5 ft

$\cos 15 = \frac{AC}{60}$

$=> 0.9659..... = \frac{AC}{60}$

$=> AC = (0.9659.....) \times 60 = 57.9555.....$ ≈ 58 ft

Area of ΔABC = $\frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2$

4 0

3 years ago