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Law Incorporation [45]
3 years ago
15

A square rotated about its center by 360º maps onto itself at different angles of rotation. You can reflect a square onto itself

across different lines of reflection.

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0

A square rotated about its center by 360º maps onto itself at 4 different angles of rotation. You can reflect a square onto itself across 4 different lines of reflection.

ale4655 [162]3 years ago
5 0

Solution:

When a square is rotated by an angle of 360°, at all four places that is when it is rotated by angle of 90° each time, at all four instances it is congruent  to original square.

So, when a square is reflected along a line ,there are four lines through which square looks symmetrical.

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The total cost of n shirts is $15. The shirts are priced at a constant rate of $3 each.
Flauer [41]

Answer:

3*x=15

Step-by-step explanation:

i think-

5 0
3 years ago
Read 2 more answers
Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

The exact value of cos 15°.

Solution:

$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}

Using half-angle identity:

$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}

$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}

Using the trigonometric identity: \cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}

            $=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}

Let us first solve the fraction in the numerator.

            $=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}

Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

            $=\sqrt{\frac {2+\sqrt{3}}{4}}

Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

           $=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}

5 0
3 years ago
What is the value of 2-2x-3y5 for x = 2 and y = -4?
a_sh-v [17]
2 - 2(2) - 3(-4)5
2 - 4 + 60 = 58
The answer is 58
6 0
3 years ago
what do i write for this " Write a problem that requires adding 1 to the quotient when interpreting the remainder."
Mariana [72]
You should write a ( real world situation ) question that can only have whole numbers as a solution because you would divide and then you can not have a fraction left over so instead you add one. For instance there are 132 students going on a field trip. 20 students can fit on each bus. how many buses are needed? 7 because when you divide 132 by 20 you get 6 remainder 12. You can not just make 12 students walk to the location so you would add an extra bus.
6 0
3 years ago
Could someone help me for this?
lina2011 [118]

Answer:

x = - \frac{5}{3} , x = \frac{5}{2}

Step-by-step explanation:

to find the points of intersection equate the 2 equations , that is

7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )

6x² - 5x - 25 = 0 ← factor the quadratic on left side

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × - 25 = - 150 and sum = - 5

the factors are - 15 and + 10

use these factors to split the x- term

6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )

3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term

(2x - 5)(3x + 5) = 0

equate each factor to zero and solve for x

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - \frac{5}{3}

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

3 0
2 years ago
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