The surface area of a right square pyramid is 50 square inches. If the sides of the base and the slant height of the pyramid are
each multiplied by 4, what is the surface area of the new cone?
*Brainliest for first correct answer*
(It's not answer B)
*Brainliest for first correct answer*
(It's not answer B)
2 answers:
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Step-by-step explanation:
You need to translate all the points to the right 3 and up 6
Therefore, you are going to use this formula:
(x,y) ⇾ (x + 3, y + 6)
This is the same format as the previous problem, if you have noticed.
Using this, plug in each coordinate, starting with P (5, -1)
(5, -1) ⇾ ( 5 + 3, -1 + 6)
(5, -1) ⇾ ( 8, 5 )
P = (8, 5)
Now point Q, (0, 8)
(0, 8) ⇾ (0 + 3, 8 + 6)
(0, 8) ⇾ ( 3, 14 )
Q = (3, 14)
And last but not least, the point R, (7, 5)
(7, 5) ⇾ (7 + 3, 5 + 6)
(7, 5) ⇾ ( 10, 11 )
R = (10, 11)
Therefore, P = (8, 5), Q
= (3, 14), R
= (10, 11) is your answer. This is the 4th option or D.
Hope this for you to understand this a bit more! =D
For this case we have that by definition, the volume of a cylinder is given by:
Where:
A: It is the radius of the cylinder
h: It's the height
We have according to the data that:
Substituting in the equation we have:
ANswer: