The surface area of a right square pyramid is 50 square inches. If the sides of the base and the slant height of the pyramid are
each multiplied by 4, what is the surface area of the new cone?
*Brainliest for first correct answer*
(It's not answer B)
*Brainliest for first correct answer*
(It's not answer B)
2 answers:
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Answer:
x = 2root(22)
see image.
Step-by-step explanation:
The triangle shown is one big triangle cut into two more smaller triangles: one medium-sized and one smaller.
ALL THREE TRIANGLES ARE SIMILAR BY AA.
Set the two smaller triangles up so you can see the corresponding sides. x is the short leg in one triangle and it is the long leg in the smallest triangle. Set up a proportion.
22/x = x/4
crossmultiply
x^2 = 22•4
x^2 = 88
square root both sides.
x = sqroot(88)
x = 2sqroot(22)
see image.
Answer:
Everything but A and C
Step-by-step explanation:
Answer:
50
Step-by-step explanation:
since the Pythagorean theorem is
√
b is the bottom line (48)
a is the right line (14)
c is the top line (c)
plug that in
√
then do the exponets
= 14 * 14 = 196
= 48 * 48 = 2304
then add them together
196 + 2304 = 2500
√2500
the sqrt of 2500 is 50 (50 * 50 = 2500)
c = 50
your answer is 50
hope this helps:)