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EleoNora [17]
3 years ago
11

Can someone please help me with my hw.

Mathematics
2 answers:
valina [46]3 years ago
8 0

Answer:

The answer is 1,440

Step-by-step explanation:

Lostsunrise [7]3 years ago
6 0

Answer:

<h2>1, 440</h2>

Step-by-step explanation:

<em>g</em><em>o</em><em>d</em><em> </em><em>b</em><em>l</em><em>e</em><em>s</em><em>s</em><em> </em>

<em><u>f</u></em><em><u>r</u></em><em><u>o</u></em><em><u>m</u></em><em><u> </u></em><em><u>p</u></em><em><u>h</u></em><em><u>i</u></em><em><u>l</u></em><em><u>i</u></em><em><u>p</u></em><em><u>p</u></em><em><u>i</u></em><em><u>n</u></em><em><u>e</u></em><em><u>s</u></em><em><u> </u></em>

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HELPPPPP ASAPPPP!!!!!!
In-s [12.5K]

Hey there!!

Let's take the number as x and y

Given,

The sum of x and y = 12

One number is 2 more than the other

Let's take y = x + 2

Equations

x + y = 12

As we know y = x + 2 , plug the value in

x + x + 2 = 12

2x + 2 = 12

Subtract 2 on both sides

2x = 10

Divide by 5 on both sides

x = 5

y = 2 + x

y = 7

The numbers are 5 and 7

Hope my answer helps!

3 0
4 years ago
Read 2 more answers
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values
Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

u(0)=4,u'(0)=7,v(0)=2,v'(0)=1

a.We have to find the values of \frac{d(uv)}{dx}

\frac{d(u\cdot v)}{dx}=u'v+uv'

Using this formula

Then , we get

[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18

[\frac{d(uv)}{dx}]_{x=0}=18

b.\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}

c.

[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}

[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}

d.\frac{d(-6v-9u)}{dx}=-6v'-9u'

[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69

[\frac{d(-6v-9u)}{dx}]_{x=0}=-69

3 0
3 years ago
PLEASE HELP ASAP I WILL GIVE BRAINSLET TO THE CORRECT ANSWER!!!!!!!!!!
cestrela7 [59]

<u>Answer</u>:

Therefore has one solution.

<u>explanation</u>:

Given equations:

6x + y = -7

-24x -7y = 25

Make y the subject:

6x + y = -7

y = -7 - 6x ..............equation 1

-24x -7y = 25

-7y = 25 + 24x

y = (25 + 24x)/-7 ..........equation 2

Solve them simultaneously:

(25 + 24x)/-7 = -7 - 6x

25 + 24x = -7 (-7 - 6x)

25 + 24x = 49 + 42x

42x - 24x = 25- 42

18x = -24

x = -\frac{4}{3}

Then y is:

y = -7 - 6x

y = -7 - 6( -\frac{4}{3})

y = 1

Has one separate value of x and y: (  -\frac{4}{3} , 1 ); so it has one solution.

3 0
3 years ago
NEED HELP ON this problem
V125BC [204]
12 + v/5 = -3

step 1. subtract 12 from both sides...
v/5 = -15
step 2. Do the opposite operation, since your diving 5, multiply 5 and -15
v = -75

the variable 'v' equals -75

6 0
3 years ago
What are the solutions to the equation x2 + 4x - 5 = 0?
s344n2d4d5 [400]
2+2x-5=0? It’s x=3/2
4 0
3 years ago
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