Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).
-6(-2)^2 - 4^2 - 3(-2x^4)
Multiply -6(-2)^2.
12^2 - 4^2 - 3(-2x^4)
Subtract 12^2 and -4^2.
8 - 3(-2x^4)
Distribute -3(-2x^4).
8 + 6x^4
Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.
X^2-9=0 add 9 to both sides
x^2=9 take the square root of both sides
x=±3
Xy - x - y + 1
explanation: distribute (x-1)(y-1) —> x(y-1) - 1 (y-1) —> xy - x - 1(y-1) —> xy - x - y + 1
3 times x equals to 646
3x=646
- 1 1/10 + (-1 2/5)
- 1 1/10 + (-1 4/5)
-2 5/10
-2 1/2
