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xxTIMURxx [149]
3 years ago
7

Red coloration in wheat seeds is a complex trait influenced by three unlinked genes, each with two different alleles A and a; B

and b; C and c. This Punnett square shows the results of a mating between two plants that are both heterozygous at all three loci. The intensity of the red color phenotype is influenced by only one of the gene products. true or false?
Biology
1 answer:
Sauron [17]3 years ago
3 0

Answer:

Red coloration in wheat seeds is a complex trait influenced by three unlinked genes, each with two different alleles A and a; B and b; C and c. This Punnett square shows the results of a mating between two plants that are both heterozygous at all three loci. The intensity of the red color phenotype is influenced by only one of the gene products. true or false?

False

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8 0
3 years ago
NEED HELP ASAP! WILL GIVE BRAINLIEST
dem82 [27]

Hey there! :D

When we are talking about gametes, we can use a punnet square, or in this case, common knowledge. If two of the alleles for one phenotype are the same, we can infer there will only be two variations of the genotype. (because there are two dominant SS genes) We already know that "D" must be the answer. Firstly, there will be one allele for each gene, so there will always be an "S" and a "T" no "SS" or "tt" (when talking about gametes). That leaves us with B and D but there is no recessive "s" in the original genotype, so the answer must be "D".

I hope this helps!

~kaikers

7 0
3 years ago
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lutik1710 [3]

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a

Explanation:

8 0
3 years ago
Write a short essay on how will you protect natural resources.
USPshnik [31]

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By reducing, reusing and recycling of non-renewable resources. Non-human species must be disturbed only to meet the basic needs. Planting of more and more trees to save our forest resources. Seeking alternatives to non-renewable resources.

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7 0
2 years ago
A phenotypic ratio for a dihybrid cross is predicted to be 9:3:3:1. The experimental values are:
Maslowich
Two traits that we are examining are the color (purple/white) and the smoothness. 
In our sample, we have 135 individuals ( 75 +28+24+8= 135).

Since we know that expected ratio of a dihybrid cross, is <span>9:3:3:1 we can calculate what is the expected values of each phenotype is.

So, for the white wrinkled phenotype, we expect that there will be one-sixteenth of the whole sample ( there are 16 parts of the whole sample 9+3+3+1=16).
So, we multiply the whole sample- 135 with one-sixteenth (or </span>0.0625) and get 8,4375.
When you calculate the values for all phenotypes you get results shown in the attached excel table.
When you have your expected and experimental values you compare them with a chi-square test. (The test determines if the difference between the expected and experimental results is statistically significant).


4 0
3 years ago
Read 2 more answers
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