1.53*10^10 because the total value would = 17,000(9.0*10^5) which is equals, when multiplied, 15300000000. Which is equivalent to 1.53*10^10 <span />
-9-(12-3x)=-9-1*(12)-1*(-3)=-9-12+3x=-21+3x=3(x-7)
13. The words are telling you
.. HT +TS = HM +MS +2
.. (2x +1) +(x) = (x +1) +(x +2) +2
.. 3x +1 = 2x +5 . . . . . . . . . . . . . . collect terms
.. x = 4 . . . . . . . . . . . . . . . . . . . . . add -2x-1
HT +TS = 3x +1 = 3*4 +1 = 13 miles
The route via the theater is 13 miles.
Via the mall, the route is 11 miles.
14. Solve this the way you would any 2-step linear equation. Subtract terms that don't have h, and divide by the coefficient of h.
S = 2πr^2 +2πrh
S -2πr^2 = 2πrh
(S -2πr^2)/(2πr) = h
If you like, you can rearrange this to
.. h = (S/(2πr)) -r
Answer: x=-6
Sorry, I am only able to find the x :(
Step-by-step explanation:
Step 1: Add -xy^3 to both sides.


Step 2: Add -5 to both sides.

Step 3: Divide both sides by -1.

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Answer:
Therefore,the level of paint is rising when the bucket starts to overflow at a rate
cm per minute.
Step-by-step explanation:
Given that, at a rate 4 cm³ per minute,a cylinder bucket is being filled with paint
It means the change of volume of paint in the cylinder is 4 cm³ per minutes.
i.e
cm³ per minutes.
The radius of the cylinder is 20 cm which is constant with respect to time.
But the level of paint is rising with respect to time.
Let the level of paint be h at a time t.
The volume of the paint at a time t is


Differentiating with respect to t

Now putting the value of 



To find the rate of the level of paint is rising when the bucket starts to overflow i.e at the instant h= 70 cm.

Therefore, the level of paint is rising when the bucket starts to overflow at a rate
cm per minute.