Need answer in a simplified fraction 9/20 x 10/9 equals what

postnew [5]

Answer:

(c) BC ≅ BC, reflexive property

Step-by-step explanation:

The conclusion of this proof derives from CPCTC and the SAS congruence postulate. In order for SAS to apply, corresponding sides and the angle between them must be shown to be congruent. The congruence statement ...

ΔABC ≅ ΔDCB

tells you these pairs of sides and angles are congruent:

AB ≅ DC . . . . statement 2
∠ABC ≅ ∠DCB . . . . statement 4
BC ≅ CB . . . . (missing statement 5)
AC ≅ DB . . . . statement 7

That is, the statement needed to complete the proof is a statement that segment BC is congruent to itself. That congruence is a result of the reflexive property of congruence.

4 0

2 years ago

\int\limits^0_∞ cos{x} \, dx

JulijaS [17]

Answer:

$\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty)$

General Formulas and Concepts:

Pre-Calculus

Unit Circle
Trig Graphs

Calculus

Limits
Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$
Integrals
Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$
Trig Integration
Improper Integrals

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^0_\infty {cos(x)} \, dx$

Step 2: Integrate

[Improper Integral] Rewrite: $\displaystyle \lim_{a \to \infty} \int\limits^0_a {cos(x)} \, dx$
[Integral] Trig Integration: $\displaystyle \lim_{a \to \infty} sin(x) \bigg| \limits^0_a$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle \lim_{a \to \infty} sin(0) - sin(a)$
Evaluate trig: $\displaystyle \lim_{a \to \infty} -sin(a)$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle -sin(\infty)$

Since we are dealing with infinity of functions, we can do a numerous amount of things:

Since -sin(x) is a shift from the parent graph sin(x), we can say that -sin(∞) = sin(∞) since sin(x) is an oscillating graph. The values of -sin(x) already have values in sin(x).
Since sin(x) is an oscillating graph, we can also say that the integral actually equates to undefined, since it will never reach 1 certain value.

∴ $\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty) \ or \ \text{unde}\text{fined}$