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blagie [28]
3 years ago
6

Calculate the slope of the line for Graph B.

Mathematics
2 answers:
miss Akunina [59]3 years ago
8 0

Answer:

Slope = -1

Step-by-step explanation:

You are provided with two points on the line (-5, 7) and (1,1).

Slope = \frac{y_{2} -y_{1}}{x_{2} -x_{1}}

Slope = \frac{7-1}{-5-1} =\frac{6}{-6} =-1

Alex3 years ago
7 0

Answer:

-1

Step-by-step explanation:

rise = -2

run = 2

Slope = rise / run

= -2/2 = -1

Since also the angle made by the line and x axis in anti clockwise direction is > 90° the slope will be-ve .

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Victoria is designing an image to be projected onto a screen. Her design is shown
Nataliya [291]

Answer:

13 ug

Step-by-step explanation:

Victoria is designing an image to be projected onto a screen. Her design is shown

below.

Victoria's Design

What is the total area, in square centimeters,

of Victoria's design?

8 cm

4 cm

4 cm

4 cm

10 cm

14 cm

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6 0
3 years ago
At town has a population of 13000 and grows at 2.5% every year. What will be the population after 5 years, to the nearest whole
zubka84 [21]

Answer:

the answer will be 14708

4 0
2 years ago
Read 2 more answers
A) Enter the corresponding values on the quadratic formula:
ollegr [7]

The answer is a = 0, b = -5, and c= 39.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

A quadratic equation means that it should have at least one squared term.

<u>step 2</u> :

The standard form is ax² + bx + c = 0.

<u>step 3</u> :

The solution to the quadratic equation is usually written in the form

x = (-b ± √(b2 − 4ac))/(2a)

where a = coefficient of x^2

           b = coefficient of x

          c = constant term

<u>step 4</u> :

The given equation is -5x +32.

∴ The answer is a = coefficient of x^2 = 0

                           b = coefficient of x = -5

                          c = constant term = 39

7 0
3 years ago
Find the distance traveled by a particle with position (x, y as t varies in the given time interval. x = 3?sin2 t, y = 3?cos2 t,
ANTONII [103]
Assuming the particle's position is given by

\begin{cases}x(t)=3-\sin2t\\y(t)=3-\cos2t\\0\le t\le4\end{cases}

then the distance traveled over the interval is

\displaystyle\int_{t=0}^{t=4}\sqrt{\left(\dfrac{\mathrm dx(t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy(t)}{\mathrm dt}\right)^2}\,\mathrm dt
=\displaystyle\int_0^4\sqrt{(-2\cos2t)^2+(2\sin2t)^2}\,\mathrm dt
=\displaystyle\int_0^4\sqrt{4\cos^22t+4\sin^22t}\,\mathrm dt
=\displaystyle2\int_0^4\mathrm dt
=2(4-0)=8
5 0
3 years ago
Simplify 11x+3y-5x-2y<br>​
mojhsa [17]

Answer: 6x+y

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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