CD is called the middle base and is equal to :(AB + EF)/2
CD = <span>(AB + EF)/2
4x = [(x</span>²+10) + (8-x)]/2
8x = x²+10+8-x
8x= x²-x+18
x²-9x+18 = 0
x' = [-b+√(b²-4.a.c)]/2a & x" = [-b-√(b<span>²-4.a.c)]/2a
x'= 6 and x" = 3, So we have2 values of x</span>
Answer:
0.1
Step-by-step explanation:
0.3 x 7= 2.1
2.1 - 2= 0.1
Answer:
5 pigs
Step-by-step explanation:
A farmhouse shelters 16 animals, some are pigs, and some are ducks. Altogether there are 42 legs. How many pigs are there?
Let us represent:
Number of pigs = x
Number of ducks = y
Our system of equations is given as:
A farmhouse shelters 16 animals, some are pigs, and some are ducks.
x + y = 16...... Equation 1
x = 16 - y
Altogether there are 42 legs.
Ducks have 2 legs(feet) , pigs have 4 legs,
4x + 2y = 42..... Equation 2
We substitute
16 - y for x in Equation 2
Hence:
4(16 - y) + 2y = 42
64 - 4y + 2y = 42
Collect like terms
- 4y + 2y = 42 - 64
-2y =- 22
y = -22/-2
y = 11 ducks
Solving for x.
x = 16 - y
x = 16 - 11
x = 5 pigs
Therefore, we have 5 pigs
Let x be the number of treats bought
Let y be the pounds of food bought
25= 2y+x
Given that she has buys 9 pounds of dog food:
25= 2(9)+x
25=18 +x
25-18 =x
7=x
With the money she has left over, she can buy 7 treats.
Hope I helped :)
Answer:
Step-by-step explanation:
If x varies directly as the product of p and m, and inversely with y, the relation can be written ...
x = k(pm)/y . . . . where k is the constant of proportionality
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This can be solved for k:
k = xy/pm
For the given values, the value of k is ...
k = (2)(4)/((0.5)(2)) = 8
Then the relation between the variables can be written ...
(xy)/(pm) = 8
