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3 years ago

12+3/5x−8−7/10x=?

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

7 0

Answer:

−1 /10 x+4

Step-by-step explanation:

Group like terms

=3/5x-7/10x+12-8

add

-10x+12-8

1/10x=x/10

-x/10+12-8

−1 /10 x+4

If you need more help just ask

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The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t

jasenka [17]

Answer:

width: 24 cm
height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

(4x)(6x) = 384 cm^2

x^2 = 16 cm^2 . . . . . divide by 24

x = 4 cm

The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

24 cm by 36 cm

_____

Comment on margins

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

Alternate solution

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

w = √(3072/12) = 16 . . . . matches above solution.

Generic solution

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

A = (w +s)(a/w +t)

A' = t - sa/w^2

For A' = 0, ...

w = √(sa/t)

and the height is ...

a/w = a/√(sa/t) = √(ta/s)

Then the ratio of width to height is ...

w/(a/w) = w^2/a = (sa/t)/a

width/height = s/t . . . . . . the premise we started with, above

6 0

2 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

Oumou is buying tile for her kitchen. The area of Oumou’s rectangular kitchen, in square feet, can be found by using the express

SOVA2 [1]

Explanation: “The distributive property is where a number or value is distributed into a whole equation. Based on the work below as you can see I “distributed” 5 to (3m+4n) meaning I multiplied 5&3m and 5&4n, when I multiply 5&3 that give me 15, and when I multiply 5&4 that gives me 20. So when finally simplified my new equation is 15m+20n”

Make sure when you is the distributive property that you always add the variables because it will be wrong.