All categories

3 years ago

Helppppppp and fast

Mathematics

2 answers:

grin007 [14]3 years ago

8 0

Answer:

its 11 1/4

Step-by-step explanation:

cause I'm big brain

Rufina [12.5K]3 years ago

7 0

Answer:

it's 2 11 1/4

Step-by-step explanation:

You might be interested in

∆ABC has A(-3, 6), B(2, 1), and C(9, 5) as its vertices. The length of side AB is units. The length of side BC is units. The len

leonid [27]

Answer:

AB = 7.07 units

BC = 8.06 units

AC = 12.04 units

Step-by-step explanation:

To find the length for each side of the triangle, apply the distance formula between each pair of vertices.

AB

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07$

BC

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06$

AC

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04$

4 0

3 years ago

the direction angle for vectors 135° the X component of the vector is -3 what is the Ywhat is what what is the Y component of th

blagie [28]

Well, the X component (assuming x is the horizontal) is equal to RCosZ

Where Z is the angle and R is the size of the resultant

Substitute into formula :

X component = RcosZ
-3 = Rcos135°
R = -3/cos135°
R = 4.24264...
R = 4.24 (2dp)

The vertical component (or Y component) is equal to RSinZ

Vertical component = RSinZ
= 4.24264... × Sin135°
= 3

The answer is 3

Please feel free to ask any questions you have

3 0

3 years ago

(-4k4 + 14 + 3k?) + (-364 - 14k - 8)

zepelin [54]

Answer:

it equals 38 because eit makes alot of sense and I e it with

5 0

3 years ago

What is the derivative of the function below?

11111nata11111 [884]

$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$

8 0

3 years ago

On Tuesday Conrad had 3 times as many sales as on Monday. On Wednesday, he had 9 times as many sales as on Monday. Over the thre

Vlad1618 [11]

Answer:

Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.

Step-by-step explanation:

Let x be the no. of sales on Monday

We are given that On Tuesday Conrad had 3 times as many sales as on Monday.

So, Conrad had sales on Tuesday = 3x

We are also given that On Wednesday, he had 9 times as many sales as on Monday.

So, Conrad had sales on Wednesday = 9x

Over the three days, he had a total of 728 sales

So, x+3x+9x=728

13x=728

$x=\frac{728}{13}$

x=56

Conrad had sales on Tuesday = 3x =3(56)=168

Conrad had sales on Wednesday = 9x=9(56)=504

Hence Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.

7 0

3 years ago