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Olenka [21]
2 years ago
13

Select proportional or not proportional to correctly classify the pair of ratios 1.8/7.2 and 0.4/1.6

Mathematics
1 answer:
andreev551 [17]2 years ago
8 0

Answer: proportional

Step-by-step explanation: just took the quiz

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The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many pages
Ivanshal [37]
Lionel had 250 pages copied

This is because 20/.08=250.
8 0
3 years ago
Read 2 more answers
3. Given that a is 30% of b, find the value of a/4b
Karolina [17]

Answer:

a/4b = 0.075

Step-by-step explanation:

a = 30% of b

a = 30/100 × b

a = 0.3b

The value of a/4b is calculated as:

= 0.3b/4b

= 0.075

6 0
2 years ago
Which points of the following points are solutions to the equation 3x-4y-8=12
Natali [406]

Answer:

(0, -5), (4, -2), (-16, -17)

Step-by-step explanation:

I attach your full question in the image below

The equation is

3x-4y-8=12

Which can be rewritten as

3x-4y =12 +8

3x-20 = 4y

y = (3/4)*x - 5

We need to check each individual case

(0,-5)

y = (3/4)*(0) - 5  

y = -5

True

(4,-2)

y = (3/4)*(4) - 5  

y = -2

True

(8,2)

y = (3/4)*(8) - 5  

y = 1

False

(-16,-17)

y = (3/4)*(-16) - 5  

y = -17

True

(-1,-8)

y = (3/4)*(-1) - 5  

y = -23/4

False

(-40,-34)

y = (3/4)*(-40) - 5  

y = -35

False

(0,-5) (4,-2) and (-16,-17) are the solutions

8 0
3 years ago
Complete the proof, word bank at bottom
Naya [18.7K]

Answer:

Step-by-step explanation:

2) definition of angle bisector

4) division property of equality

5) division property of equality

6) substitution property

7) SAS similarity

7 0
2 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0
3 years ago
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