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2 years ago

Help please!!! It’s for Geometry

Mathematics

1 answer:

mixas84 [53]2 years ago

3 0

Answer:

-5

Step-by-step explanation:

because it is on the - side because there is a post side and a - side

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PLEASE HELP ME ON THIS AND SHOW UR WORK<br> THX

swat32

When an exponential function is given as
f(x)=ab^x, and
knowing that b^0=1, that means that
f(0)=ab^0=a value of function when x=0, or the initial value.
In the case of
f(x)=20.b^x, f(0)=20.b^0 = 20 (initial value)

If b=1.2, then the hourly growth rate is (1.2-1)=0.2=20%.
If b=1.85, then the hourly growth rate is (1.85-1)=0.85=85%.

4 0

3 years ago

Use the fact that 15⋅324=4,860.What is the exact product of 1.5⋅3.24?

Anastaziya [24]

Answer:

Step-by-step explanation:

From the question, we are informed that 15⋅324=4,860. Thee exact product of 1.5⋅3.24 will be:

= 1 × 5 × 3 × 24

= 360

The answer will therefore be 360

4 0

2 years ago

1. If you deposit $4350 at 2.32% interest, compounded continuously, what would your ending

I am Lyosha [343]

Answer:

$4999.69

Step-by-step explanation:

F = Pe^(rt)

F = $4350 * e^(0.0232 * 6)

F = $4999.69

8 0

3 years ago

Find the equivalent expression for x2 + 4x + 4

Vlada [557]

Step-by-step explanation:

Add.

2x+4x=6x

6x+4=6x+4

4 0

2 years ago

Read 2 more answers

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

2 years ago