Answer:
The answer to this question is given below in the explanation section.
Explanation:
This program is written in C++.
#include <iostream>
using namespace std;
int main()
{
string word;// variable for taking user input
int cond;// to set condition true if user preses the stop and exit from loop
cout<<"Enter word: \n";
cin>>word;
do// start while loop
{
if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit
{
cond=0;
}
else//otherwise loop continue
{
cout<<" You Entered "+ word +"\n";
cout<<"Enter word: \n";
cin>>word;
cond=1;
}
}
while(cond == 1);// if user don't enter word "stop" loop run continuesly.
cout<<"Program exit";
return 0;
}
Creating a Microsoft account for use in Visual Studio 2015 means that you will get a better and optimized user experience, with several benefits.
Some of the purposes why you should create an account are:
1. free software, training and support from Visual Studio and broad range of benefits
2. synchronized Visual Studio Settings, which means that you will have for example the same layout, window and color theme, or whatever you select in the settings, every time you log in with your account
Answer:
Subject
Explanation:
The kind of word that is pronoun in bold letters is "Subject".
In Example
We get our paychecks on Friday, and I always need mine.
There We and I are subjects.
Answer:see explanation
Explanation:
Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.
The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!
#include <stdio.h>
int main(void)
{
int countNum;
int i;
countNum = 22;
for ( i = countNum; i > 0; i--) {
if (i == countNum){
printf("Ready!\n");
}
printf("%d\n",i);
}
printf("Go!\n");
return 0;
}
