All categories

2 years ago

Will you please help me with this question?

Mathematics

1 answer:

insens350 [35]2 years ago

4 0

Answer:

i can't see it make it more noticeable

You might be interested in

Daniel is drawing a plan for a new animal pen for his farm. The rectangle plotted in the coordinate plane represents the pen, me

Nat2105 [25]

Answer:

22ft

Step-by-step explanation:

I just did the edge.

3 0

2 years ago

What’s 7= y-2/3 if you’re solving for y

Rus_ich [418]

Answer:

y = 23/3

Step-by-step explanation:

Simplify both sides of equation

7 = y + -2/3

Flip equation

y + -2/3 = 7

Add 2/3 to both sides

y + -2/3 + 2/3 = 7 + 2/3

y = 23/3

6 0

2 years ago

Out of 21 students in Mrs.Clarks class, 3/7 of the class are boys and 4/7 are girls. How many students in the class are girls an

lidiya [134]

Answer:

9 boys and 12 girls

Step-by-step explanation:

if you multiply the denominators by 3, you get "out of" 21. All you need to do after that is multiply the top by 3 as well and it tells you there are 9 boys and 12 girls.

8 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

A right rectangular prism has these dimensions:

ki77a [65]

Volume of rectangular prism = 1 1/3 x 5/6 x 2/3 = 4/3 x 5/6 x 2/3 = 20/27

Volume of cube = 1/6 x 1/6 x 1/6 = 1/216

Number of cubes that will pack the rectangular prism = 20/27 / 1/216 = 160

5 0

2 years ago

Read 2 more answers

Will you please help me with this question?​

Will you please help me with this question?