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saveliy_v [14]
3 years ago
7

Will you please help me with this question?​

Mathematics
1 answer:
insens350 [35]3 years ago
4 0

Answer:

i can't see it make it more noticeable

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If you use BEDMAS you should end up with an answer of 1004.
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What is the answer to (y+2y-6)+(2y-4)
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You FOIL (First, Outer, Inner, Last)
If you FOIL, you should get 2y^2 - 4y + 4y^2 - 8y +12y -24
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0.56 as a fraction in simplest form.
Vlada [557]

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14/25

Step-by-step explanation:

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3 years ago
A cylinder with a diameter of 10 inches (in.) and a cube are shown.
Scorpion4ik [409]

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C

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7 0
3 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the
Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of .

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is \pi = 0.5

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}

0.001\sqrt{n} = 2.327*0.5

\sqrt{n} = \frac{2.327*0.5}{0.001}

(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}

n = 1353732.25

Rounding up

A sample size of at least 1,353,733 is required.

5 0
3 years ago
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