To prove:

Solution:

Multiply first term by
and second term by
.

Using the identity: 

Denominators are same, you can subtract the fractions.

Using the identity: 

Using the identity: 

------------ (1)

Using the identity: 


------------ (2)
Equation (1) = Equation (2)
LHS = RHS

Hence proved.
If a polynomial is divisible by

, then

is a root of this polynomial.
Here (x-a) is equal to x+2:

So -2 is a root of the polynomial. That means <span>x³-6x²+kx+10</span>=0 for x=-2. Now substitute -2 for x in the equation and solve for k: