The Areas of each of the composite shapes are;
1) A = 30 m²
2) A = 20 yd²
3) A = 615.4 km²
4) A = 23 cm²
5) A = 168 m²
6) A = 86.3 m²
<h3>How to find the area of regular shapes?</h3>
1) Area of parallelogram = bh
A = 6 * 5
A = 30 m²
2) Area of Triangle = ¹/₂bh
A = ¹/₂ * 10 * 4
A = 20 yd²
3) Area of circle is;
A = πr²
A = 3.14 * 14²
A = 615.4 km²
4) Area of this composite figure is;
A = Area of Triangle - Area 0f rectangle
A = (¹/₂ * 13 * 10) - (7 * 6)
A = 65 - 42
A = 23 cm²
5) Area of composite figure is;
A = 2(¹/₂ * (16 + 8) * 3) + (16 * 6)
A = 72 + 96
A = 168 m²
6) Area of composite figure;
A = ¹/₂ * (15 + 8) * 7.5
A = 86.3 m²
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Answer: it will have three terms. It will be in the form ax^2 + bx + c
The "a" could be any number, but if it is "1", it will be left out.
The "+" sign is often a minus sign.
^2 means "squared" and is usually shown as an exponent, but my keyboard don't have that capability now.
Examples
x^2 + 5x +4
5x^2 +13x -6
2x^2 -11x + 15
Answer:
<em>9.</em>
Step-by-step explanation:
3 * √)0^2 + 3^2)
= 3*3
= 9.
Given:
ABCD is a cyclic quadrilateral.
m∠C = 43°
To find:
The measure of ∠A.
Solution:
<em>In cylic quadrilateral, opposite angles are supplementary.</em>
⇒ m∠A + m∠C = 180°
⇒ m∠A + 43° = 180°
Subtract 43° from both sides.
⇒ m∠A + 43° - 43° = 180° - 43°
⇒ m∠A = 137°
The measure of ∠A is 137°.
Answer:
-3
Step-by-step explanation:
We have two points
( -3,1) ( -1,-5)
We can use the slope formula
m = (y2-y1)/(x2-x1)
= ( -5-1)/(-1- -3)
= (-5-1) / (-1+3)
= -6/2
= -3
