On all of them? Which numbers?
Answer:
uh. Yeah totally
Step-by-step explanation:
Answer:
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Step-by-step explanation:
Let x number of $5, y number of $10 and z number of $20
The number of $5 bills exceeds twice the number of $10 bills by 4.
Therefore, x = 2y + 4
The number of $20 bills is 6 fewer than the number of $10 bills.
Therefore, z = y - 6
A wallet contains $460 in $5, $10, and $20 bills.
Therefore,
5x + 10y + 20z = 460
Substitute x and y into equation
5(2y+4) + 10y + 20(y-6) = 460
10y + 20 + 10y + 20y - 120 = 460
40y - 100 = 460
40y = 460 + 100
40y = 560
y = 14
- Put the value of y into x = 2y + 4 and solve for x
x = 2(14) + 4
x = 32
- Put the value of y into z = y - 6 and solve for z
z = 14 - 6
z = 8
Hence, the each type of bills,
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Answer:
The Red set is greater than the other set because most of the date is clumped to the right and most data sets have the numbers go from smallest to greatest so Yes, the data sets are significantly greater than the other data set.
Step-by-step explanation:
The intercept would be 5 Y if you acually solve that equation
