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3 years ago

Help! what’s the answer. I looked it up but it’s not right too many different answers

Mathematics

1 answer:

Ne4ueva [31]3 years ago

6 0

7x+2y=-17

steps:
x=2x + 5x
y=3y - y
sum=-5 -12

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Write a quadratic function with two real zeros.

satela [25.4K]

The formula for quadratic equation is given by:

x² - (sum)x + (product) = 0

so if we have real roots of 3 and 5

 x² - (3 + 5)x + (3*5) = 0
 x² - 8x + 15 = 0

so if we have real roots of -3 and -6

 x² - (-3 - 6)x + (-2*-6) = 0
 x² - (-9x) + 12 = 0
 x² + 9x + 12 = 0

5 0

3 years ago

Lan scores 5 out of 60 mark test.what is his score as a percentage to 1 decimal place

artcher [175]

Answer:

.1 approx.

Step-by-step explanation:

5/60 and x/100%

Cross multiplying...

5 x 100% = 5

5/60 ~= .1

( I dunno if I am right, so please check first.)

6 0

3 years ago

If I'm 16 years old, how many months, days, hours, minutes, and seconds old am I?

irakobra [83]

16*12=months
16*365=days
Then take that answer and multiply it by 24 for hours then take that number and multiply it by 60 for minutes and then take that number and multiply it by 60 for seconds.

8 0

3 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

2 years ago

What is the slope of the line? Anwer

amm1812

The slope of the line is 1/3

5 0

3 years ago

Read 2 more answers