All categories

2 years ago

What is the area of a shaded region in the quarter circle radius 12

Mathematics

1 answer:

garik1379 [7]2 years ago

3 0

Answer:

I guess that the shaded area is a quarter of a circle of radius 12 units.

Is easy to know that the area, will be equal to the quotient between the area of a circle of radius 12, and 4

We know that the area of a circle of radius R is:

A = pi*R^2

in this case, R = 12

pi = 3.14

Then:

A = 3.14*12^2 = 452.16

And a fourth of that is:

A/4 = (452.16)/4 = 113.04

The area of the shaded region is 113.04 square units

You might be interested in

Which describes the calculations that could be used to solve this problem?

Darya [45]

Answer:

Subtract 37 – 13. Then divide the difference by 4.

Step-by-step explanation:

After the box:

37 - 13 left

No. of bags:

(37 - 13)/4

4 0

3 years ago

A 4 meter long ladder leans against a 90 degree wall at a 68 degree angle.

Alenkinab [10]

Answer:

Step-by-step explanation:

We use trig to answer these questions:

sin x = opposite side of a triangle / hypotenuse

cos x = adjacent side / hypotenuse

Construct a right triangle with hypotenuse 4 m and lower angle 68 degrees.

The height of the top of the ladder is then defined by:

sin 68 degrees = height / 4 m, which yields (4 m)(sin 68) = height =

3.71 m

and the distance of the bottom of the ladder from the wall as follows:

cos 68 degrees = horizontal distance / hypotenuse =

1.50 m

3 0

2 years ago

You are painting the outside of a 36-foot fence that goes around a square playground. There are 4 equal sections. You have paint

kvv77 [185]

36/4 x 1/4 = 36/16 or 2 4/16 or 2 1/4

5 0

2 years ago

Read 2 more answers

Answer this question

jeka57 [31]

I hope this helps you

6 0

2 years ago

Hey can anyone pls answer these math problems!!

Zepler [3.9K]

Answer:

1={5 and 3} 2={0} 3={0.209 and 4.791} 4={-3 and 4} 5={1 and 9} 6={-4.303 and -0.697}

Step-by-step explanation:

Your probably confused on what a, b, and c means.

The problems are written like this.

$ax^2+bx+c=0$

That formula finds the zeros.

For example 1:

$x^2-8x+15=0\\ax^2-bx-c\\a=1\\b=-8\\c=15$

Then use the formula

$x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-(-8)+-\sqrt{-8^2-4(1)(15)} }{2} \\x=\frac{8+-\sqrt{64-60} }{2} \\\\x=\frac{8+-2}{2}\\$

If plus then 5, if minus then 3

CHECK:

$x^2-8x+15=0\\5^2-8(5)+15=0\\25-40+15=0\\0=0\\3^2-8(3)+15=0\\9-24+15=0\\0=0$

Hope this helps you understand how to do this by yourself. Now to do the rest ;-;

5 0

2 years ago

What is the area of a shaded region in the quarter circle radius 12​

What is the area of a shaded region in the quarter circle radius 12