What is the solution to the system of equations?

Tomtit [17]

The correct answer is: The point where the lines meet. Hope this helps!!

8 0

3 years ago

Noam chose 3 songs from a pile of 20 songs to play at a piano recital. What is the probability that she chose The Entertainer, S

Alenkasestr [34]

$|\Omega|={_{20}C_3}=\dfrac{20!}{3!17!}=\dfrac{18\cdot19\cdot20}{2\cdot3}=1140\\|A|=1\\\\P(A)=\dfrac{1}{1140}\approx0.09\%$

6 0

3 years ago

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Smallville is 104 miles east of Bigtown. Medburg is 206 miles east of Bigtown. How many miles is Medburg from Smallville?

malfutka [58]

Answer:

102 miles

Step-by-step explanation:

5 0

3 years ago

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Assume women’s heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. a. If one wom

Zarrin [17]

Answer: a) 0.5636 b) 0.7881

Step-by-step explanation:

We assume that women’s heights are normally distributed .

Let x be the random variable that represents the shoe sizes.

Also, The population mean = $\mu=\text{63.6 inches}$ ; Standard deviation: $\sigma=\text{2.5 inches}$

a) Formula for z:-

$z=\dfrac{x-\mu}{\sigma}$

Put x= 64, we get

$z=\dfrac{64-63.6}{2.5}=0.16$

Now, the probability that the male shoe sizes are greater than 8 :-

$P(z$

Hence, the probability that her height is less than 64 inches = 0.5636

b. Sample size : n= 25

Then , the formula for z :-

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Put x= 64, we get

$z=\dfrac{64-63.6}{\dfrac{2.5}{\sqrt{25}}}=0.8$

Then, the probability that they have a mean height less than 64 inches.:_

$P(z$

Hence, the probability that they have a mean height less than 64 inches. =0.7881

7 0

3 years ago

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What is the p-value? -- Researcher Jessie is studying how the fear of going to the dentist affects an adult's actual number of v

Vesnalui [34]

Answer:

Two, one for the 14 responses (number of visits) by the adults who fear going to the dentist and one for the 31 responses (number of visits) by the adults who do not fear going to the dentist.

Step-by-step explanation:

Hello!

1)

You want to test if the average visits to the dentist of people who fear to visit it are greater than the average visits of people that don't fear it.

In this case, the statistic to use is a pooled Student t-test. The reason I've to choose this test is that one of your sample sizes is small (n₁= 14) and the t-test is more accurate for small samples. Even if the second sample is greater than 30, if both variables are normally distributed, the pooled t-test is the one to use.

H₀: μ₁ = μ₂

H₁: μ₁ > μ₂

α: 0.10

t=<u> (X₁[bar]-X₂[bar]) - (μ₁ - μ₂)</u> ~ t $_{n₁+n₂-2}$

Sₐ√(1/n₁+1/n₂)

Where

X₁[bar] and X₂[bar] are the sample means of both groups

Sₐ is the pooled standard deviation

This is a one-tailed test, you will reject the null hypothesis to big numbers of t. Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis), and in this case, is also one-tailed.

P(t $_{n₁+n₂-2}$ ≥ t $_{H0}$ ) = 1 - P(t $_{n₁+n₂-2}$ < t $_{H0}$ )

Where t $_{H0}$ is the value of the calculated statistic.

Since you didn't copy the data of both samples, I cannot calculate it.

2)

Well there was one sample taken and separated in two following the criteria "fears the dentist" and "doesn't fear the dentist" making two different samples, so this is a test for two independent samples. To check if both variables are normally distributed you need to make two QQplots.

I hope it helps!

3 0

3 years ago