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wariber [46]
3 years ago
11

Hello! :)

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0
The answer is decreasing and linear.Therefore B.Please mark me brainliest im 100% sure it’s the right answer.
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What is the solution to y - 7 = -7?<br> A. y = 14<br> B. y = 7<br> C. y = 0<br> D. y = -7
horrorfan [7]

If you add 7 to negative 7, it would be y=0.

Answer: y=0

7 0
3 years ago
Read 2 more answers
Please answer these three questions. There are 3 images attached below and they apply to each question, in order.
statuscvo [17]
1a. It is because each x only has 1 y and it has an equation
1b. It is not a function because each x has more than 1 y.
1c. It is not a function because there can be no equation written for this graph.
7 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
One of the most popular indonesian traditional ensemble​
Arte-miy333 [17]

Answer:

Gamelan

Step-by-step explanation:

a gamelan, is gamelan

8 0
2 years ago
One positive integer is 5 times another positive integer and their product is 320. What are the positive integers?​
NeTakaya
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 5y
xy = 320

Substitute the first equation into the second equation
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)

The integers are (x, y) = (40, 8).
7 0
2 years ago
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