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ra1l [238]
3 years ago
13

If a car is moving at the speed of 60 miles per hour how many miles would a car travel i 120 minutes

Mathematics
1 answer:
sertanlavr [38]3 years ago
8 0

Answer:

120 miles

Step-by-step explanation:

120minutes= 2hour

2×60÷1=120 (miles)

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Rewrite 2(x + 3y - 2z) using the Destributive Property
zloy xaker [14]

Answer:

2x+6y-4z

Step-by-step explanation:

multiply the two by each term and coefficient inside of the parentheses

6 0
3 years ago
5 ( x + y) +3 (2x +y)​
satela [25.4K]

Answer:

11x + 8y

Step-by-step explanation:

(5x + 5y) + 3 ( 3 · 2x + 3y)

(5x + 5y) + (6x + 3y)

5x + 5y + 6x + 3y

5x + 6x + 5y + 3y

11x + 8y

7 0
2 years ago
A Ship travels at a steady Speed.
SpyIntel [72]

Answer:

speed=24km/h or 6.67m/s

Step-by-step explanation:

Given data:

time taken = t =43 hours

distance covered = d = 1032 km

to find:

speed of the ship = v =?

solution:

as we know that speed is defined as the distance covered by an object in unit time.Formula

speed = distance covered /time taken

speed = 1032km/43hours

speed =24km/h or in international system of units the answer is 6.67m/s

4 0
4 years ago
( 3m - 2 ) + 2 - m + 3
tia_tia [17]

Answer:

nxxjdndndndkdkd

snns

Step-by-step explanation:

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7 0
3 years ago
can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as
tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
3 years ago
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