Ask question

Ask question

All categories

3 years ago

11

95 points need help match these to each other please

2 answers:

krek1111 [17]3 years ago

5 0

Answer:

1. Least common multiple

2. Least common denominator

3. multiple

4. solve

5. solution

Step-by-step explanation:

wel3 years ago

5 0

Answer: 1: connects with box number one

2: connects with box number five

3: connects with box number two- i think

4: connects with box number three

5: connects with box number four

♡ Glued

You might be interested in

Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

3 years ago

(4,2);x=-3 how do you solve this problem

Alexandra [31]

Find the equation of the line and plug in the x value that gives you which is -3? i am not very sure so i am sorry if i am wrong

6 0

3 years ago

Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

Natalija [7]

Answer:

x=3 , x=-3

Step-by-step explanation:

$e^{lnx^2} -9= 0$

Add 9 on both sides

$e^{lnx^2}=9$

To remove base 'e' we take ln on both sides

$ln e^{lnx^2}=ln9$

$lnx^2=ln(9)$

Both sides have ln , so we make the terms equal

$x^2=9$

Take square root on both sides

$x=+-3$

x=3 , x=-3

5 0

3 years ago

Gina works at a diner.She earns 6$ each hour plus tips.In one week,She worksed 37 hours a week and earned 434$ in tips.How much

finlep [7]

False.

6(x)+434=?
x= number of hours so problem can be rewritten as
6(37)+434
———
222+434=
656

3 0

3 years ago

If a circle has a diameter of 23 inches, then the radius will be_____?

Troyanec [42]

Answer:

half. what is half of 23? 11.5 inches

Step-by-step explanation:

3 0

2 years ago