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3 years ago

What is the missing value 2/6=x/15

Mathematics

1 answer:

boyakko [2]3 years ago

8 0

Answer:

x= 5

Step-by-step explanation:

Your teacher should have explained it but give me points please

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The midpoint of FG is (6-4) and the coordinates of point Fare (-3, 6) What are the coordinates of point G?

lora16 [44]

Answer:

(15,-14)

Step-by-step explanation:

Given that,

The midpoint of FG is (6-4) and the corrdinates of F are (-3,6).

Let (x,y) be the coordinates of point G. Using mid point formula,

$\dfrac{x+(-3)}{2}=6\ \text{and}\ \dfrac{y+6}{2}=-4\\\\x-3=12\ \text{and}\ y+6=-8\\\\x=15,\ \text{and}\ y=-14$

So, the coordinates of G are (15,-14).

4 0

3 years ago

Hey I’m having trouble finding out how to divide fractions

solniwko [45]

The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.

5 0

2 years ago

During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim

dem82 [27]

Because u would have to find the undercorse of 010-1 witch makes the out of part by 6

3 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago

Thanks who ever helped

NeTakaya

Answer:

60 × 50 = 3000

7 × 50 = 350

60 × 4 = 240

7 × 4 = 28

3000 + 350 + 240 + 28 =3618

54 × 67 = 3618

3 0

2 years ago