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Nitella [24]
3 years ago
5

Solve for angles a and b

Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

b=42

a=81

Step-by-step explanation:

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Rewrite the function f(x) = -2(x+3)^2 – 8 in the form f (x) = ax²+bx+c.
OverLord2011 [107]

Answer:

-2x^{2}-12x-26

Step-by-step explanation:

(x+3)^2 = x^2+6x+9

-2(x^2+6x+9)-8

-2x^2-12x-18-8

-2x^2-12x-26

8 0
4 years ago
Cheryl sells 21 children tickets, 23 adult tickets, and 7 senior tickets for the junior high soccer game. Write the ratio adult
Elis [28]
I don’t think Cheryl can sell kids
6 0
3 years ago
I will mark brainliest please someone help
NikAS [45]

M midpoint of CD, given

MD = 3, given

MD = CM, def. of midpoint

CM = 3, substitution

6 0
3 years ago
which of the following ordered pairs is a solution of the equation -2y + 9 = -x? A.(2,5) B.(-3,15) C.(4,-1)
vlada-n [284]

Answer:

Step-by-step explanation:

-2y + 9 = -x

x - 2y = -9

Plug in each set of points and see if the equation holds true.

A. 2 - 2(5) = ?

B. -3 - 2(15) = ?

C. 4 - 2(-1) = ?

I don't think that any of them work.

4 0
3 years ago
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
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