All categories

3 years ago

A $300 suit is marked down by 20%. Find the sale price rounded to the nearest dollar.

Mathematics

2 answers:

Mademuasel [1]3 years ago

7 0

Answer:

$240

Step-by-step explanation:

Debora [2.8K]3 years ago

6 0

Answer:

240 is the mark down.

Step-by-step explanation:

1 - .20 = 0.8

0.8 x 300 = 240

You might be interested in

Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx

Rudiy27

If we use the substitution $u = \tan x$ , then $du = \sec^2 {x}\ dx$ . If you try substituting just $u$ and $du$ into the integrand, though, you'll notice that there's a $\sec^2x$ left over that we have to deal with.

To get rid of this problem, use the identity $\tan^2 x + 1 = \sec^2 x$ and substitute in the left side of the identity for the extra $\sec^2x$ , as shown:

$\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx$
$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$

From there, we can substitute in $u$ and $du$ , and then evaluate:

$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du$
$= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}$
$= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})$
$= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}$

8 0

3 years ago

A piece of string is 325 centimeters long. You need the string to be 114 meters long. How many centimeters should you cut off?

anygoal [31]

You should cut off 211cm

3 0

4 years ago

Can I get some help on these two question im confused

Sedbober [7]

Answer:

for 1 I am guessing D and for 2 I am guessing B.

5 0

3 years ago

Need Help Rn!!!

fgiga [73]

It would be 5850 hope you get it right:)

7 0

3 years ago

Find the probability of rolling less than a 2

irina1246 [14]

Answer:

1/6

Step-by-step explanation:

prob of less than 2 = prob of rolling a 1 = 1/6

5 0

3 years ago