Answer:
c) -x^3 + x^2 - 1
Step-by-step explanation:
Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2
(u/v)(x) = u(x)/v(x)
Now plug in the given functions in the above formula, we get
= (x^5 - x^4 + x^2) / -x^2
We can factorize the numerator.
In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.
= x^2 (x^3 - x^2 + 1) / - x^2
Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.
(u/v)(x) = (x^3 - x^2 + 1) / -1
When we dividing the numerator by -1, we get
(u/v)(x) = -x^3 + x^2 - 1
Answer: c) -x^3 + x^2 - 1
Hope you will understand the concept.
Thank you.
Answer: To simplify this problem you combine the like terms in the equation (numbers with the same variables.)
Demo: 12r + -4r = 8r
Using the factor label method, you would set up your ratio like so:
9514 1404 393
Answer:
- units for 20: minutes
- units for 30: degrees Celsius
Step-by-step explanation:
The problem statement tells you the function value is in degrees Celsius, and the function argument is in minutes.
units for 20: minutes
units for 30: degrees Celsius
Summarizing the question,
Principle(P)=$100
Rate (r)=12%=0.12
Amount (A)=3×P=$300
Time=t=?
n=no of times the interest is compouned per year=4
Then,
A=P{(1+r/n)}^(n×t)
or,300=100×{1+0.12/4}^(4×t)
or,300/100=(1+0.03)^(4×t)
or,3=1.03^(4×t)
Taking log on both sides,
log3=log[(1.03)^(4×t)]
or,log3= (4×t)×log(1.03)
or,4t=log3/log(1.03)
or,t=log3/[4×log(1.03)]
or, t=9.29175...
t=9.3 years ANS!!!
