Question

What's the midpoint between (1,6) and (3,1) need help

Answer 1

Answer:

$(2, \frac{7}{2} )$

Step-by-step explanation:

The midpoint between two points is:

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$ when the given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the points (1,6) and (3,1)

$= (\frac{1+3}{2} , \frac{6+1}{2} )\\= (\frac{4}{2} , \frac{7}{2} )\\= (2, \frac{7}{2} )$

Therefore, the midpoint between (1,6) and (3,1) is $(2, \frac{7}{2} )$.

I hope this helps!

Answer 2

The answer is 2 or 3.5