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2 years ago

6

V is the midpoint of UW. If UV = x + 2 and VW = 2x, what is VW?

2 answers:

erica [24]2 years ago

8 0

Answer:

VW = 4

Step-by-step explanation:

Since V is the midpoint of line UW, we can say that the measure of UV is equal to VW (see def. of midpoint). Thus, we can generate the equation using the statements provided, leading us to this equation: x+2 = 2x. We can then subtract x on both sides, leading us to 2 = x, or x = 2.

We were given that VW = 2x, thus the measure of VW is equal to 2(2) or 4.

(BONUS: since we know that VW ≅ UV, then the measure of UV is also equal to 4, which when applied to the formula for UV (x+2) we get the equation for UV, x+2=4. This is a way to prove that x=2, as 2+2=4. We can also use this knowledge to find the total length of this line segment, which would be 8, as 4+4=8)

Elan Coil [88]2 years ago

3 0

Answer:

8 units

Step-by-step explanation:

x + 2 = 2x

2 = 2x - x

x = 2

uW = 2(2+2) = 8

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grin007 [14]

Answer:

x = -1 , y = -4 , z = -4

Step-by-step explanation:

Solve the following system:

{-x - 5 y + z = 17 | (equation 1)

-5 x - 5 y + 5 z = 5 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Swap equation 1 with equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

-x - 5 y + z = 17 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Subtract 1/5 × (equation 1) from equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 1 by 5:

{-x - y + z = 1 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 2 by 4:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Add 2 × (equation 1) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

0 x+3 y - z = -8 | (equation 3)

Swap equation 2 with equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x - y+0 z = 4 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z/3 = 4/3 | (equation 3)

Multiply equation 3 by 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z = 4 | (equation 3)

Multiply equation 3 by -1:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 3 to equation 2:

{-x - y + z = 1 | (equation 1)

0 x+3 y+0 z = -12 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Divide equation 2 by 3:

{-x - y + z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 2 to equation 1:

{-x + 0 y+z = -3 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Subtract equation 3 from equation 1:

{-x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Collect results:

Answer: {x = -1 , y = -4 , z = -4

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What are the solutions to the quadratic equation <img src="https://tex.z-dn.net/?f=x%5E2%20%2B40%3D0" id="TexFormula1" title="x^

Mandarinka [93]

Answer:

In disguise right arrow In Standard Form a, b and c

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and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5

z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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