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Darya [45]
3 years ago
13

What is Lender or Creditor in Business Math?​

Mathematics
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

<em>a</em><em> </em><em>credito</em><em>r</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>leader</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>entitled</em><em> </em><em>to</em><em> </em><em>rec</em><em>eive</em><em> </em><em>the</em><em> </em><em>pa</em><em>y</em><em>ment</em><em> </em><em>f</em><em>rom</em><em> the</em><em> </em><em>browser</em>

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This is elemntry math what is this world coming to ? number 1 and 4 should be easy just put them in order imm really confused on the other one
7 0
3 years ago
Which of the following series are convergent?
Westkost [7]

Answer:

All of them

Step-by-step explanation:

According to the ratio test, for a series ∑aₙ:

If lim(n→∞) |aₙ₊₁ / aₙ| < 1, then ∑aₙ converges.

If lim(n→∞) |aₙ₊₁ / aₙ| > 1, then ∑aₙ diverges.

(I) aₙ = 10 / n!

lim(n→∞) |(10 / (n+1)!) / (10 / n!)|

lim(n→∞) |(10 / (n+1)!) × (n! / 10)|

lim(n→∞) |n! / (n+1)!|

lim(n→∞) |1 / (n+1)|

0 < 1

This series converges.

(II) aₙ = n / 2ⁿ

lim(n→∞) |((n+1) / 2ⁿ⁺¹) / (n / 2ⁿ)|

lim(n→∞) |((n+1) / 2ⁿ⁺¹) × (2ⁿ / n)|

lim(n→∞) |(n+1) / (2n)|

1/2 < 1

This series converges.

(III) aₙ = 1 / (2n)!

lim(n→∞) |(1 / (2(n+1))!) / (1 / (2n)!)|

lim(n→∞) |(1 / (2n+2)!) × (2n)! / 1|

lim(n→∞) |(2n)! / (2n+2)!|

lim(n→∞) |1 / ((2n+2)(2n+1))|

0 < 1

This series converges.

3 0
3 years ago
What is negative 56 divided by -7
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The answer is just use a calc lol 8
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Answer:

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Step-by-step explanation:


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4 years ago
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What expression can be used to determine the total cost of buying c pounds of cashews for $3.85
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Answer:

B

Step-by-step explanation:

8 0
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