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jeka57 [31]
2 years ago
5

An object that weighs 1 on Earth weighs 1.19 pounds on Neptune. Suppose a dog weighs 9 pounds on earth. How much would the same

dog weigh on Neptune?
(40 points!)
Mathematics
2 answers:
nadya68 [22]2 years ago
6 0

Answer:

f 1 pound on Earth is equal to 1.19 pounds on Neptune all you have to do is multiply the number of Earth pounds by their Neptunian equivalent: 9x1.19=10.71 the dog would weigh 10.71 pounds :) I hope this makes sense :)

valina [46]2 years ago
3 0

Answer:

They will weigh 10.71 on Neptune

Step-by-step explanation:

We can write a ratio to solve

1 Earth              9 Earth

--------------  = ---------------

1.19 Nept           x Neptune

Using cross products

1x = 1.19 * 9

x =10.71

They will weigh 10.71 on Neptune

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5.6+4.1=9.7 The dog is now 9.7 kg.
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Determine whether each of the functions log(n + 1) and log(n2 + 1) is o(log n)
larisa86 [58]
Assuming the order required is as n-> inf.

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8 0
3 years ago
VGravel is being dumped from a conveyor belt at a rate of 50 ft3/min. It forms a pile in the shape of a right circular cone whos
kupik [55]

Answer:

0.325 ft/min

Step-by-step explanation:

To solve we must follow the following steps:

First, the volume of a cone is given by the equation:

Vc = (1/3) * Pi * (r ^ 2) * h

where r is the radius and h is the height.

they tell us that the height is equal to twice the radius, therefore

h = 2r; r = h / 2

replacing r in the volume of the cone:

Vc = (1/3) * Pi * ((h / 2) ^ 2) * h

solving we have:

Vc = (1/3) * Pi * (1/4) * (h ^ 2) * h

Vc = (1/12) * Pi * h ^ 3

They give us the change in volume with respect to time, that is, dV / dt = 50

It can also be expressed in the following way:

dV / dt = (dV / dh) * (dh / dt)

We know V, so we can derive with respect to h, we are like this:

dV / dh = 3 * (1/12) * Pi * h ^ 2

dV / dh = (1/4) * Pi * h ^ 2

we know that h is equal to 14, therefore:

dV / dh = (1/4) * Pi * 14 ^ 2

dV / dh = (1/4) * 3.14 * 196 = 153.86

Now if we replace

dV / dt = (dV / dh) * (dh / dt)

50 = 153.86 * (dh / dt)

(dh / dt) =  50/158.36

(dh / dt) =  0.3249

This means that the change in height with respect to time is 0.325 feet per minutes.

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