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Tema [17]
3 years ago
9

Write a program that reads in exam scores and displays the average score and the high score.

Computers and Technology
1 answer:
Lunna [17]3 years ago
3 0

Answer:

74

Explanation:

because with this mark 74 I have or ready pass my course

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Write an If/else statement to check whether host is online. If it is online, then print system is online otherwise print system
Reika [66]

Answer:

from socket import *

hostname = input('Enter the host to be scanned: ')

ip_add = gethostbyname(hostname)

connections = [ ]    

for i in range(133, 136):

   s = socket(AF_INET, SOCK_STREAM)

     

   conn = s.connect_ex((ip_add, i))

   print(conn)

   connections.append(conn)

if 0 in connections:

   print ('Host is online')

   s.close()

else:

   print ('system is unreachable')

Explanation:

The python source code above scans for all the available range of ports in the provided hostname, if any port is available, the host is online else the program print the error message "system is unreachable.

4 0
3 years ago
The efficiency and effectiveness of a logistics/supply chain operation are constrained by the location of plants and warehouses
Vika [28.1K]

Answer:

True.

Explanation:

7 0
3 years ago
The following is part of a log file taken from the machine on the network with the IP address of 192.168.1.106:__________.
Phantasy [73]

Answer:

Port scan targeting 192.168.1.106.

Explanation:

In the following question, there is some part of the question and options is missing.

In the following statement, when a file log is taken from the computer system which has Internet Protocol address is given in the statement and by the further details of the statement in which time and the port destination by examine those details of the Internet Protocol, the following port scan targeting the IP address 192.168.1.106.

3 0
3 years ago
Why is it good to be a computer programmer?​
liubo4ka [24]

Answer:

It's your wish become other professions like doctor, engineer are also good. But in this profession you can make apps, websites and can do hacking. Which is are cool things to do. But every profession is best at it's profession.

Explanation:

If you like my answer than please mark me brainliest

5 0
2 years ago
Computer Networks - Queues
lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time T_w in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w =  λ × T_w

r /  λ = w / λ  +  ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s  = \dfrac{1000}{64*1000}

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05    (i.e the average packet waiting time)

T_s = 0.015625

T_r =  0.05 + 0.015625

T_r =  0.065625

However; the  mean number of arrival per second λ is;

r = λ × T_r

λ = r /  T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus;  the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets  w waiting to be served is calculated using the formula

w =  λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0
3 years ago
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