Answer:
code = 010100000001101000101
Explanation:
Steps:
The inequality yields 
, where M = 16. Therefore,
The second step will be to arrange the data bits and check the bits. This will be as follows:
Bit position number Check bits Data Bits
21 10101
20 10100
The bits are checked up to bit position 1
Thus, the code is 010100000001101000101
Answer and Explanation:
Given that total number of records in a file = 100000
Each record consists of= 240 bytes
Given that B= 2400 bytes.
Then total blocks in file = 100000 records * 240 / 2400
= 10000 blocks.
Time that will take for exhaustive read
= s + r + b.btt
= 16 + 8.3 + (10000) * 0.8
= 8024.3 msec
Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.
Hence, X (s + r + btt) > 8024.3
X (16+8.3+0.8) > 8024.3
X > 8024.3/25.1
So that, X > 319.69
Hence, atleast 320 random reads should be made to search the file
The answer is C to this question
Answer:
1. is the answer
Explanation:
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