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zvonat [6]
3 years ago
8

Please help meeeee pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee and thankyouuuuuuuuuuuuuuuu

Mathematics
1 answer:
Nonamiya [84]3 years ago
4 0

Answer:

40$

Step-by-step explanation:

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WILL MARK BRAINLIEST IF YOU ANSWER BOTH QUESTIONS WITH SOLUTION
11Alexandr11 [23.1K]

Answer:

1. = 3xy + x - 2y - 4

2. = d^2(2c^3-8c^2d+3d^2)

Step-by-step explanation:

= 9x^2y^2 + 3x^2y - 6xy^2 - 12xy/3xy

First factor the top equation ….

= 3xy(3xy + x - 2y - 4)/3xy

If the top and the bottom both carry 3xy, you can cancel out both of them leaving you with ….

= 3xy + x - 2y - 4

= -16c^6d^6 + 64c^5d^7 - 24c^3d^8/-8c^3d^4

First factor the top equation ....

= -8c^3d^6(2c^3-8c^2d+3d^2)/-8c^3d^4

If the top and the bottom both carry -8c^3 you can cancel out both of them leaving you with ….

= <u>d^6</u>(2c^3-8c^2d+3d^2)/d^4

Apply the exponent rule with d^6 ....

= <u>d^4</u><u>d^2</u>(2c^3-8c^2d+3d^2)/d^4

cancel out d^4 ....

= d^2(2c^3-8c^2d+3d^2)

8 0
2 years ago
What is 3/16 as decimal
LenaWriter [7]
Put 3 divided by 16 into your calculator
8 0
3 years ago
How do you solve 27?
dedylja [7]

We have

\left(\dfrac{2}{3}\right)^x=\dfrac{2^x}{3^x}

And we want

\dfrac{2^x}{3^x}=\dfrac{16}{81}=\dfrac{2^4}{3^4}

Another way to read it is

\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4=\left(\dfrac{2}{3}\right)^x

It should be clear that the solution is x=4

8 0
3 years ago
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Answer: 60

Step-by-step explanation:

As JH=22 and JK=82, this means HK=60.

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2 years ago
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I took a look at the picture and the right answer for this question would be A
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3 years ago
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