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2 years ago

Integral rational trigonometric

Mathematics

1 answer:

abruzzese [7]2 years ago

8 0

Substitute x = 3 - 2 cos(θ) and dx = 2 sin(θ) dθ (where "sin" = "sen"). So we have

∫ sin(θ) / (3 - 2 cos(θ)) dθ = 1/2 ∫ 1/x dx

= 1/2 ln|x| + C

= 1/2 ln(3 - 2 cos(θ)) + C

(We can remove the absolute value because -1 ≤ cos(θ) ≤ 1, so 1 ≤ 3 - 2 cos(θ) ≤ 5, and |x| = x when x ≥ 0.)

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Irina-Kira [14]

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Step-by-step explanation:

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2 years ago

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Paladinen [302]

<h2> Rectangular Areas and Perimeters</h2>

The perimeter of a rectangle is given by:

$\boxed{\bold{Perimeter = 2 (length + width)}}$

In the problem we have these data:

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2 years ago

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GarryVolchara [31]

Answer:

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Step-by-step explanation:

Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.

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2 years ago

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valkas [14]

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Step-by-step explanation:

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2 years ago

Integral rational trigonometric ​

Integral rational trigonometric