I'm not good at math i cant help
<u>Answer:</u>
The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.
<u>Solution:</u>
Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)
We have to find the line equation which is perpendicular to above given line and passing through the given point.
Now, let us find the slope of the given line equation.

We know that, <em>product of slopes of perpendicular lines is -1.
</em>
So, 1
slope of perpendicular line = -1
slope of perpendicular line = -1
Now let us write point slope form for our required line.

y – (-2) = -1(x – (-3))
y + 2 = -1(x + 3)
y + 2 = -x – 3
x + y + 2 + 3 = 0
x + y + 5 = 0
y = -x -5
Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.
Hello :
let the slope : a and ; b the slope of the line : 5x - 3y = 8
<span>the line that is perpendicular to 5x-3y=8 so : a×b = - 1
but :
5x - 3y = 8... y = (5/3)x - 8/3 when : b = 5/3
</span><span> the slope intercept form of the equation of the line that is perpendicular
to 5x-3y=8 is : y = (5/3)x +c </span>
Step-by-step explanation:
<h2>
Sum of two complementary angle is 90°</h2><h2 /><h2>
so. </h2><h2>
<R+<S =90°</h2><h2>
12x-3+7x-2=90°</h2><h2>
19x-5=90°</h2><h2>
19x=95°</h2><h2>
X= 5</h2>
<h2>
<R= 60-3=57°</h2>
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time t it takes for the ball to hit the ground, we are looking for the height of the ball when it is on the ground. Of course the height of anything on the ground is 0, so if we set s(t) = 0 and solve for t, we will find our answer.
and factor that however you are currently factoring in class to get that
t = -.71428 seconds or
t = 1.42857 seconds (neither one of those is rational so they can't be expressed as fractions).
We all know that time will never be a negative value, so the time it takes this ball to hit the ground is
1.42857 seconds (round how you need to).