Ask question

Ask question

All categories

3 years ago

11

Maria receives a commission of 11.5% for each pair of shoes she sells she earned $207 in commission last week what was the dolla

r amount of shoes she sells

2 answers:

Anastasy [175]3 years ago

7 0

I'm pretty sure she sold 18 pairs

Ivenika [448]3 years ago

4 0

Answer:

$1800

Step-by-step explanation:

To find the amount of commission she earns, we multiply the amount of sales by the percent of the commission.

She earns 11.5% commission; 11.5% = 11.5/100 = 0.115.

Let x be the unknown amount of sales. This gives us 0.115x.

Since the commission equals $207, this gives us the equation

0.115x = 207

Divide each side by 0.115:

0.115x/0.115 = 207/0.115

x = 1800

You might be interested in

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago

I really dont understand this question, help? i dont need steps or anything

Agata [3.3K]

Answer:

Step-by-step explanation:

135 degrees is an exterior angle. meaning the interior angle is 45. meaning x is 45 because of the isosceles triangle theorem that states if two sides are equal on a triangle then their angles opposite those are congruent. a triangle measures up to 180 in general. so 45 plus 45 is 90. 180 minus 90 is 90. so angle x is 45 and angle y is 90

6 0

3 years ago

Standard rate of pay 40 hours. Gets 175% for overtime. One week Erik works regular 40 hours and has 16 hours of overtime. He mak

devlian [24]

Standard rate of pay 40 hours. Gets 175% for overtime. One week Erik works regular 40 hours and has 16 hours of overtime. He makes $680 that week. Which equation would solve for the standard rate of pay?

7 0

3 years ago

Read 2 more answers

Which inequality has the solution set shown on the graph?

professor190 [17]

Answer:

c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The owner of BobCats R Us paid his personal MasterCard bill using a company check. What is the correct entry to record the trans

charle [14.2K]

Credit cash; debit withdrawals

7 0

3 years ago