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olchik [2.2K]
2 years ago
15

PLEASE HELPPPP!!!!!!!

Mathematics
1 answer:
Strike441 [17]2 years ago
6 0

Answer:

Subtract 4 from each side

Step-by-step explanation:

x + 4 > -8

Subtract 4 from each side

x + 4-4 > -8-4

x>-12

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The Magic Carpet charges $90 for installation and $9 per square yard of carpeting. The Carpeteria's installation price is $50 bu
Sophie [7]

Answer:

The cost of the carpet at Magic Carpet is: 90 + 9*(area of carpet)

The cost of carpet at Carpeteria is: 50 + 13*(area of carpet)

The algebraic expression for which the cost is the same is: 90 + 9*(area of carpet) = 50 + 13*(area of carpet)

The area of carpet for which the cost is the same is: 10 square yard

Step-by-step explanation:

6a) The cost for magic carpet:

This company charges a fixed fee and a price for each square yard of carpeting, therfore the expression for the cost is:

cost = 90 + 9*a

Where a is the area of carpet to be installed.

6)b) The cost for Capeteria:

This company also charges a fixed fee and a price for each square yard of carpeting, so the expression is:

cost = 50 + 13*a.

6) c) The algebraic expression for the cost to be the same in both stores:

90 + 9*a = 50 + 13*a

6) d) We need to solve the expression above for a:

50 + 13*a = 90 + 9*a

13*a - 9*a = 90 - 50

4*a = 40

a = 40/4 = 10

8 0
2 years ago
Please someone help meeeee!!!
Ostrovityanka [42]

Answer:

Reflection across the y-axis and translation (slide) down by 1 unit.

7 0
3 years ago
Read 2 more answers
What is the product of Five-ninths and Seven-eighths?
Rom4ik [11]

Answer:

Improper fraction form:103/72 Mixed number form: 1 32/72 Decimal form: 1.4035 with 5 repeating

Step-by-step explanation:

3 0
3 years ago
Compare the functions below:
dezoksy [38]

the function g(x)-- -----------><span>I could model it as a second degree equation
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4 0
2 years ago
Suppose that three numbers are selected one by one, at random, and without replacement, from the set of integers {1, 2, 3, . . .
fiasKO [112]

A - the third number falls between the first two

B - the first number is smaller than the second

P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\\\ |\Omega|=n(n-1)(n-2)\\\\ |B|=\dfrac{n!}{2}\\\\ |A\cap B|=\dfrac{\dfrac{n!}{2}}{3}=\dfrac{n!}{6}\\\\ P(A\cap B)=\dfrac{\dfrac{n!}{6}}{n(n-1)(n-2)}=\dfrac{n!}{6n(n-1)(n-2)}=\dfrac{(n-3)!}{6}\\ P(B)=\dfrac{\dfrac{n!}{2}}{n(n-1)(n-2)}=\dfrac{n!}{2n(n-1)(n-2)}=\dfrac{(n-3)!}{2}\\\\ P(A|B)=\dfrac{\dfrac{(n-3)!}{6}}{\dfrac{(n-3)!}{2}}\\\\ P(A|B)=\dfrac{(n-3)!}{6}\cdot\dfrac{2}{(n-3)!}=\dfrac{1}{6}=\dfrac{1}{3}

3 0
3 years ago
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