<span>33.3333
i think, best of luck btw :)</span>
Start by writing it out like this. there are no missing values. do you need help solving?
Given info:
Compound Interest = Rs.1290
Rate of Interest = 15% p.a
Time = 2 years
<h3>Formula we have to know:-</h3>

<u>Where</u>
C.I = Compound Interest
P = Principle
R = Rate of Interest
N = Time

Here
C.I = Rs.1290
R = 15%
N = 2 years
Principle = ?
Now,Calculating the sum (Principle) borrowed by Rachna
![\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%20%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7BC.I%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%281%20%20%2B%20%5Cdfrac%7BR%7D%7B100%7D%20%5Cbigg%29%5E%7Bn%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
Substituting the given values
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%281%20%20%2B%20%5Cdfrac%7B15%7D%7B100%7D%20%5Cbigg%29%5E%7B2%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B%281%20%5Ctimes%20100%29%20%2B%2015%7D%7B100%7D%20%5Cbigg%29%5E%7B2%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B115%7D%7B100%7D%20%5Cbigg%29%5E%7B2%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B115%7D%7B100%7D%20%5Ctimes%20%5Cdfrac%7B115%7D%7B100%7D%20%20%5Cbigg%29%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B13225%7D%7B10000%7D%20%5Cbigg%29%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%20%5Ccancel%7B%5Cdfrac%7B13225%7D%7B10000%7D%7D%20%5Cbigg%29%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%7B1.3225%20-%201%7D%20%5Cbigg%29%20%5CBigg%5D%7D%7D%7D)








<u>Hence,</u>
The sum (Principle) is Rs.4000.
Answer:
25,16,121,49
5 is the sqaure root of 25 4 is the sqaure root of 16 11 is the square root of 121 and 7 is the square root of 49
50,145,20, and 8 do not have square roots.
Answer:
2520cm²
Step-by-step explanation:
Surface area = sum of the area of all the bases.
Area of bottom base = 28 * 30 = 840
Area of right base = 25 * 30 = 750
Area of left base = 17 * 30 = 510
Area of two triangles = ( 15 * 28 ) / 2 = 210 * 2 = 420
Then add all the areas together to find surface area
Surface area = 840 + 750 + 510 + 420 = 2520cm²
Relevant Formulas:
Area of a rectangle = length * width. This formula was used to find the area of the bottom base, the right base and the left base
Area of a triangle = ( height * base length ) / 2 . This formula was used to find the area of the sides which are triangles.