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3 years ago

12

(x−4)2+y2=64

1 answer:

sdas [7]3 years ago

8 0

Answer:

(12, 0)

Step-by-step explanation:

The centre of the circle is at (4, 0) and the radius = √64 = 8.

So one point on the circle is at ((4 + 8), 0) = (12,0).

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Step-by-step explanation:

We want to simplify;

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We expand the bracket to obtain;

$8r^6s^3-9r^5s^4+3r^4s^5-2r^4s^5+5r^3s^6+4r^5s^4$

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