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Sladkaya [172]
3 years ago
5

2(2 – 2x) = –3x A. –4 B. 4 C. 6 D. 0

Mathematics
1 answer:
zlopas [31]3 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

Let's solve:

2(2−2x)=−3x

Step 1: Simplify both sides of the equation.

2(2−2x)=−3x \\ (2)(2)+(2)(−2x)=−3x(Distribute) \\ 4+−4x=−3x \\ −4x+4=−3x

Step 2: Add 3x to both sides.

−4x+4+3x=−3x+3x \\ −x+4=0

Step 3: Subtract 4 from both sides.

−x+4−4=0−4 \\ −x=−4

Step 4: Divide both sides by -1.

\frac{ - x}{ - 1}  =  \frac{ - 4}{ - 1}

Therefore, the answer will be x = 4.

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8 0
3 years ago
HELP THIS IS DUE SOON!!!
aev [14]

Answer:

x≥9

Step-by-step explanation:

Pretend the Less than or equal to sign is just an equals sign

-7x+7=-56 Solve:

-7x=-56-7

-7x=-63

For the last step, if you divide a negative number, the Sign switches. So not the sign is greater than or equal to.

x>=9

6 0
2 years ago
If your getting paid 5$ every week how long will it takes you to get 10,000$?
nikdorinn [45]
2,000
10,000 divided by 5 = 2,000
3 0
3 years ago
A machine produces 374 bolts in 33 minutes. At the same rate, how many minutes would it take to produce 272 bolts?
lesya [120]
374 = 33
272 = x

374/33 = 272/x

x=(33*272)/374=24 minutes
4 0
3 years ago
Read 2 more answers
A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 48}{12}

Z = 2.5

Z = 2.5 has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

8 0
2 years ago
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