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Zielflug [23.3K]
3 years ago
10

Simplify x^2+x-12/x^2+3x-4

Mathematics
1 answer:
zmey [24]3 years ago
8 0
The answer is \frac{x^4+4x^3-4x^2-12}{x^2}
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Question 3
Likurg_2 [28]

Answer:

27cm

Step-by-step explanation:

first, separate the 2 shapes you will find the area too. these would be the little 3 by 3 block sticking out on top, and the other piece.

to find the area, you have to do length times width.

you can start off with the 3 by 3 block. 3 times 3 = 9cm

next, you have to find the measurements of the rectangular shape. we know the width is 6cm. and the length of the whole shape is also 6cm. but we can take off the 3cm from the other shape. we now have 3cm leftover to be the length for the rectangle.

we can now find the area for the rectangle. 6 times 3 = 18cm.

last but not least, we can add the 2 measurements up to get the area of the whole shape. 9 + 18 = 27cm.

8 0
3 years ago
Im begging you PLS answer my questions
Mandarinka [93]

Answer:

sure but where are the questions??

Step-by-step explanation:

8 0
3 years ago
10% of what number is 300?
sergij07 [2.7K]

10% of what number is 300?

This means that the number is greater than 300 and in fact 10 times greater. You can create and equation. Let x be the number.

0.1x=300

x=3000

answer:3000

8 0
3 years ago
Name the property of real numbers illustrated by the following equation.
wel

Answer:

Distributive property

Step-by-step explanation:

the factor "3" which appears outside the parenthesis multiplies the two terms inside it. You perform the multiplication term by term. It is also referred to as the factor "3" distributes among the terms inside the parenthesis, multiplying each.

5 0
4 years ago
Disregard my work, but how do you get the answer? There is also a graph at the bottom which is optional to use.
kakasveta [241]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
\\\\
f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind.

since the original or "parent" function is y = x²−4x+3, if we change the "x" argument to "x-2", we end up with a horizontal shift.

the x-2 part would be in the template the Bx+C part, with B = 1 and C = -2, or a horizontal shift to the right of 2/1 or 2 units.

since the parent function has a point at (2, -1), if we move that horizontally only to the right, we'd end up at (4, -1).
7 0
4 years ago
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