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4 years ago

What is 180.5% of 99?

1 answer:

4 0

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{180.5\% of 99}}{\left( \cfrac{180.5}{100} \right)99}\implies 178.695$

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The √28 is between which two whole numbers?

Irina18 [472]

Answer:

between 5 and 6

Step-by-step explanation:

Choose 2 perfect squares either side of 28, that is

25 < 28 < 36, then

$\sqrt{25}$ < $\sqrt{28}$ < $\sqrt{36}$ , thus

5 < $\sqrt{28}$ < 6

5 0

3 years ago

Solve for g. what is g equal to?

sweet [91]

Answer:

$\displaystyle g=\frac{4\pi^2l}{T^2}$

Step-by-step explanation:

Equation Solving

Given the equation

$\displaystyle l=\frac{gT^2}{4\pi^2}$

It's required to solve it for g. Let's swap sides of the equation:

$\displaystyle \frac{gT^2}{4\pi^2}=l$

Multiply by $4\pi^2$ to remove the denominator:

$\displaystyle gT^2=4\pi^2l$

Divide by $T^2$

$\boxed{\displaystyle g=\frac{4\pi^2l}{T^2}}$

4 0

3 years ago

Catherine paid $159.00 for an MP3 player. If the price paid includes a 6% sales tax, which of the following equations can be use

Colt1911 [192]

ANSWER:

The equation is y = 1.06x, so option D is correct.

EXPLANATION:

Given:

Amount Catherine is paid for an MP3 player=$159.00

The price paid includes a sales tax= 6%

To find:

Equations that can be used to determine the price of the MP3 player before tax?

Solution:

Now, we know that, total cost = selling price of item + sales tax on item

y = x + 6% of x

y = x + $\frac{6}{100}x$

y = x + 0.06x

y = 1.06x

Hence, the equation is y = 1.06x, so option D is correct.

7 0

3 years ago

Find the unit cost of a store sells a dozen eggs for 1.99.

Charra [1.4K]

Answer: 0.16$

Step-by-step explanation: You would do 1.99 divided by 12 because 12 equals to a dozen, 1.99 divided by 12 to get 0.16 cents.

8 0

4 years ago

In the early 1970's, Canada Post started using six-character postal codes. Each postal code uses three letters and three digits

pogonyaev

A Canadian postal code looks like this:

K1A 3B1 .

So you have: letter - digit - letter - digit - letter - digit .

The question doesn't say anything about restrictions on
which letters can be used, or restrictions on repeating letters
or digits within one postal code. So as far as we know, each
letter can be any one of 26, and each digit can be any one of 10.

The total number of possibilities would be

(26·10·26) · (10·26·10) = 17,576,000 .

In the real world, though, (or at least in Canada), Postal codes
don't include the letters D, F, I, O, Q or U, and the first letter
does not use W or Z. When you work it out with these restrictions,
it means there's a theoretical limit of 7.2 million postal codes.
The practical limit is a bit lower, as Canada Post reserves some
codes for special functions, such as for test or promotional purposes.
One example is the code H0H 0H0 for Santa Claus ! Other special
codes are for sorting mail bound for destinations outside Canada.

At the present time, there are a little over 830,000 active postal codes.
That's about 12% of the total possibilities, so there are still plenty of codes
left for expansion.

4 0

3 years ago