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laiz [17]
2 years ago
8

Pls help and thankssss

Mathematics
1 answer:
34kurt2 years ago
7 0

Answer:

270 is the answer

<em>-Sumin <3</em>

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Find the quotient. Simplify your answer.<br> 7y/6 divides by z/-2
HACTEHA [7]

Answer:

-7y/3z

Step-by-step explanation:

When dividing fractions, we flip the second one so that we can multiply the 2 fractions. When we do this, we get 7y/6 * -2/z. When we multiply the numerators and denominators, we get -14y/6z. Simplifying (dividing the numerator and denominator by 2), we get -7y/3z.

7 0
3 years ago
4( 3/4 + x) = 11. if you can figure it out 20 points​
sineoko [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
CAN someone help me with this pls<br> WILL GIVE BRAINLIEST
Flura [38]

Answer:

the answer would be $394.00

Step-by-step explanation: Brainliest please

because you divide 187.15 by 19 and that will be what she makes for zero than you multiply 9.85 by 40 then you get 394

3 0
3 years ago
Evaluate the expression using order of operations 8-3[{4+2}+6]=?
DENIUS [597]
<span>8- </span><span>3[{4+2}+6]
= 8 - </span><span>3[6+6]
= 8 - 3 (12)
= 8 - 36
= -28</span>
3 0
3 years ago
A large stand of fir trees occupies 24 hectares. The trees have an average density of 1 tree per 20m squared. A forester estimat
Leona [35]

Answer:

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

Step-by-step explanation:

First, let is find the total amount of fir trees that occupies the area of 24 hectares. (1 hectare = 10000 square meters)

n = \sigma \cdot A

Where:

\sigma - Surface density, measured in trees per square meter.

A - Total area, measured in square meters.

Given that \sigma = \frac{1}{20}\,\frac{tree}{m^{2}} and A = 24\,h, the total amount of fir trees is:

n = \left(\frac{1}{20}\,\frac{trees}{m^{2}}  \right)\cdot (24\,h)\cdot \left(10000\,\frac{m^{2}}{h} \right)

n = 12000\,trees

It is known that one-tenth of the tress are cut, whose amount is:

n_{c} = 0.1 \cdot n

n_{c} = 0.1 \cdot (12000\,trees)

n_{c} = 1200\,trees

If each tree will yield 300 board-feet, then the yield related to the trees that are cut is:

y = S\cdot n_{c}

Where:

S - Yield of the tress, measured in board-feet per tree.

n_{c} - Amount of trees that will be cut, measured in trees.

If n_{c} = 1200\,trees and S = 300\,\frac{b-ft}{tree}, then:

y = \left(300\,\frac{b-ft}{tree} \right)\cdot (1200\,trees)

y = 360000\,b-ft

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

8 0
3 years ago
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