Given equations are;<span>
2a + 3b = -1 ..................equation 1
3a + 5b = -2 ....................equation 2</span>
Now multiply equation 1 with (-3)
The equation will be;
-6a -9b = 3 …………………..equation 3
Now multiply equation 2 with (2)
The equation will be;
6a + 10b = -4 ……………..equation 4
Now add equation 3 and equation 4
-6a – 9b = 3
<span>6a + 10b = -4</span>
<span>------------------------------</span>
0a + b = -1
b = -1
Now put the value of b in equation 1
2a + 3(-1) = -1
2a -3 = -1
2a = -1+3
2a = 2
a=1
Thus the solution is (a,b) = (1,-1)
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</span>
Answer:
2
(
1
+
x
) (
1
−
x
) over x
^2
Step-by-step explanation:
if you didn't get that its 2
(
1
+
x
) (
1
−
x
) as the numerator and x
^2 as the denominator
Answer:
sometimes
Step-by-step explanation:
Similar figures can also be a different size, as long as they're the same shape. So both rigid transformations and dilations can create similar figures.
Answer:
(2.5, -1)
(-2.5, 1)
(-1, 2.5)
Step-by-step explanation:
