Answer: Third Choice. Thousandths
Step-by-step explanation:
<u>Concept:</u>
Here, we need to know the order and name of each place value.
Please refer to the attachment below for the specified names.
<u>Solve:</u>
<em>STEP ONE: Orde and name each place</em>
2 ⇒ One Thousands
4 ⇒ Hundreds
5 ⇒ Tens
6 ⇒ Ones
.
1 ⇒ Tenths
3 ⇒ Hundredths
8 ⇒ One Thousandths
7 ⇒ Ten Thousandths
<em>STEP TWO: Find the number [8] in the number</em>
As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is <u>Thousandths</u>.
Hope this helps!! :)
Please let me know if you have any questions
As
, the sequence
converges to zero.
If you're talking about the infinite series
well we've shown by comparison that this series must also converge because we know any geometric series
will converge as long as
.
Are you sure you want ONLY the coefficient of b? If you expand this, you will have b in 3 of 4 terms.
According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:
1
1 2 1
1 3 3 1
1 4 6 4 1
So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
Here, you want (3 + b)^4. Here's what that looks like:
3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]
Which coeff did you want?
The answer is h = 2A/(b1 + b2).
In order to find this, use all the methods for solving typically used in these types of equations. See the below example.
A = 1/2(b1 + b2)h ---> Multiply both sides by 2.
2A = (b1 + b2)h -----> Divide both sides by (b1 + b2)
2A/(b1 + b2) = h
