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Daniel [21]
3 years ago
9

Given a box of 8 color crayons (Red, Blue, Green, Orange, Yellow, Brown, Black, Purple). If I remove a single crayon randomly, a

nd without putting it back in the box, I remove a second crayon randomly, what is the probability that I will remove the Red and the Green crayon from the box
Mathematics
1 answer:
stich3 [128]3 years ago
8 0

Answer: 1/56

Step-by-step explanation:

Since the box has 8 different colors, the probability of picking any color of crayon will be 1/8.

This question relates to a probability without replacement, therefore, the probability of picking the red crayon first will be 1/8. After then, there'll be 7 crayons left and the probability of picking the green crayon next will be 1/7.

Therefore, the probability that I will remove the Red and the Green crayon from the box will be:

= 1/8 × 1/7

= 1/56

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Consecutive integers mean one after the other and their difference would one more or less.

Let the numbers be x, x +1, x +2.

Therefore x + (x+1) + (x +2) = 567
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               3x = 567 -3 = 564
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Therefore integers  x, x +1, x +2 = 188, 188+1, 188+2.
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