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lidiya [134]
3 years ago
9

Kahleela starts the engine on her small private airplane. The engine drives a propeller with a radius of 8.5 feet and its center

line 11.5 feet above the ground. At idle, the propeller rotates at a constant speed of approximately 800 revolutions per minute. The height of one propeller tip as a function of time is given by h = 11.5 + 8.5 sin(800t), where h is the height in feet and t is the time in minutes. Find h when t = 5.5 minutes.
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
6 0

Answer:

A. 3.1 feet is the answer i believe.........

Step-by-step explanation:

algol133 years ago
4 0

Answer:

a=21.1

Step-by-step explanation:

You can use the given (incorrect) equation and fill in the value of t to find h:

 h = 12.5 +9sin(750(3.5)) = 3.68 . . . . feet

__

Or, you can use the correct equation, or just your knowledge of revolutions:

 h = 12.5 +9sin(750(2π·3.5)) = 12.5 . . . . feet

in 3.5 minutes at 750 revolutions per minute, the propeller makes 2625 full revolutions, so is back where it started — at 12.5 feet above the ground.

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Vlad1618 [11]

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Step-by-step explanation:

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3 years ago
Q. Nol<br>Find the<br>radio of<br>35cm to 5m​
Step2247 [10]

Answer:

7:100

Step-by-step explanation:

35cm= 35cm

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ratio = 35:500

\frac{35}{500} ÷ \frac{5}{5} = \frac{7}{100}

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4 0
3 years ago
Point C is the center of the circle. What is the measure of angle ACB if arc ADB measures 250 degrees?
NeX [460]

Around the outside of a circle measures 360°. If arc ADB measures 250°, then arc AB measures 360-250 which is 110°. Because point C is the center of the circle, then angle ACB is a central angle. By definition of an arc intercepted by an angle, they are the exact same measure in degrees. So if arc AB = 110, then the measure of the angle ACB also measures 110.

4 0
3 years ago
PLEASE HELP
Andreyy89
1. percent increase : (new number - original number) / (original number)...x 100

<span>(22 - 20) / 20 = 2/20 = 0.1.....0.1 x 100 = 10...so there is a 10% increase</span>
7 0
4 years ago
Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1​]
blagie [28]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

3 0
3 years ago
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