Answer:
A 2√2(cos 7π/4 + i sin 7π/4)
Step-by-step explanation:
A. 2√2(cos 7π/4 + i sin 7π/4)
2 sqrt(2) ( sqrt(2)/2 - sqrt(2)/2 i)
Distribute
2-2i
This is in the fourth quadrant
B. 2√2(cos 150° + i sin 150°)
2 sqrt(2) (-sqrt(3)/2 +1/2i)
-sqrt(6) +sqrt(2) i
This is in the third quadrant (NO)
C. 2(cos 7π/4 + i sin 7π/4)
2( ( sqrt(2)/2 - sqrt(2)/2 i))
sqrt(2) - sqrt(2) i
This is the fourth quadrant
D. 2(cos 90° + i sin 90°)
2(0+i)
2i
This is on the positive y axis NO
Now we need to decide between the two in the fourth quadrant.
The point has an x coordinate of 2 and a y coordinate of -2
This aligns with point A
Answer:
the horizontal position for the left edge of the image is -4.46 cm.
Step-by-step explanation:
The horizontal midpoint of the page is:
21.59 / 2 = 10.79 cm
The horizontal midpoint of the image is given as:
30.51 / 2 = 15.25 cm
These midpoints must be on the same point in the axis.
By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.
The distance that goes beyond this leftmost edge is computed as;
This is on the negative side on the axis.
Thus the horizontal position for the left edge of the image is -4.46 cm.
Answer:
I think that the answers are B, E, and F.
Step-by-step explanation:
Don't rate me if they are wrong.
